Oleh: suhartoumm | Desember 24, 2013

Uji Linieritas dan Keberartian Koefisien Regresi

Uji Persyaratan Analisis

X Y
9 10
5 7
8 9
10 12
6 7
5 6
6 8
8 8
10 11
8 9

Penyelesaian

Uji Linieritas dan Koefisien Regresi
X Y X2 Y2 XY
5 6 25 36 30
5 7 25 49 35
6 7 36 49 42
6 8 36 64 48
8 8 64 64 64
8 9 64 81 72
8 9 64 81 72
9 10 81 100 90
10 11 100 121 110
10 12 100 144 120
∑75 ∑87 ∑595 ∑789 ∑683

Y = a + bx

Y = 1,665+0,938X

Sumber db JK RJK Fh
Reg. (b/a) 1 JK(b/a)=28,609 S2reg=JK(b/a)=28,609 S2/S2sis = 65,61
Sisa n-2 =10-2 JK(S)=3,49 S2Sisa = JK(S)    = 0,436 n-k
Tuna Cocok k-2 =5-2 JK(TC)=1,33 S2 TC = JK(TC)  = 0,44    k-2 S2TC/S2G = 1,01
Galat n-k =10-5 JK(G)=2,16 S2G = JK(G) = 0,43       n-k

Menghitung jumlah kelompok

X Kelompok n1 Y
5 }1 (2) 6 2
5 7
6 }2 (2) 7 2
6 8
8 }3 (3) 8 3
8 9
8 9
9 }4 (1) 10 1
10 }5 (2) 11 2
10 12

Berarti ada 5 kelompok

1. JK (T) = 789 = ∑Y2 = 789

2. JK (a) = (∑Y)2:n = (87):10 = 756,9

3. JK (b/a) = b[XY – [(∑X) x {(∑Y):n}]] = 0,983 x [683 –[(75) x {(87)}:10]] = 28,609

4. JK (S) = JK(T) – JK(a) – JK(b/a) = 789 – 756,9 – 28,609 = 3,49

5. JK (G) = 62 + 72 – {(6+7)2:2} + 72 + 82 – {(7+8)2:2} + 82 + 92 +92 – {(8+9+9)2:2} +

5. JK (G) = + 102 – {(10)2:2} + 112 + 122 – {(11+12)2:2} = 2,16

6. JK (TC) = JK (S) – JK (G) = 3,49 – 2,16 = 1,33

S2 reg = JK(b/a)=28,609

S2 sisa = JK(S)/n–k = {3,49:(10–2)} = 0,436

S2TC = JK(TC)/k – 2 = {1,33:(5–2)}

S2G = JKG/n – k = {2,17:(10-5)} = 0,43

Uji Keberartian Koefisien Regresi

Ho : Regresi tidak berarti

Ha : Regresi berarti

Bila Fh > Ftabel Ho ditolak

Bila Fh ≤ Ftable Ho diterima

Ternyata Fhitung > F Tabel ===> 65,61 > 5,32 (α 5%)

Berarti Ho ditolak. Atau regresi berarti….

Uji Linier Koefisien Regresi

Ho : Regresi linier

Ha : Regresi tidak linier

Bila Fh > Ftabel Ho ditolak

Bila Fh ≤ F table Ho diterima

Ternyata Fhitung < Ftabel ===> 1,01 < 11,26 (α 1%)

Berarti Ho di terima. Atau regresi linier…..


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